Instructions: This Monk test contains JK Bank Ratio and Proportion Problems with answer. This will help you in JK bank exam preparation.
This is a FREE online JK Bank Monk Test on topic JK Bank Ratio and Proportion Problems with answer. You DO NOT pay money to anyone to attend this test.
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Directions to Solve
In the following the questions choose the word which best expresses the meaning of the given word.
Results
#1. A and B together have Rs. 1210. If 4/15 of A's amount is equal to 2/5 of B's amount, how much amount does B have?
Answer: Option B
Explanation:
4 | A | = | 2 | B | |
15 | 5 |
![]() |
![]() |
2 | x | 15 | ![]() |
5 | 4 |
![]() |
3 | B |
2 |
![]() |
A | = | 3 |
B | 2 |
A : B = 3 : 2.
![]() |
![]() |
1210 x | 2 | ![]() |
= Rs. 484. |
5 |
#2. Two numbers are respectively 20% and 50% more than a third number. The ratio of the two numbers is:
Answer: Option C
Explanation:
Let the third number be x.
Then, first number = 120% of x = | 120x | = | 6x |
100 | 5 |
Second number = 150% of x = | 150x | = | 3x |
100 | 2 |
![]() |
![]() |
6x | : | 3x | ![]() |
= 12x : 15x = 4 : 5. |
5 | 2 |
#3. A sum of money is to be distributed among A, B, C, D in the proportion of 5 : 2 : 4 : 3. If C gets Rs. 1000 more than D, what is B's share?
Answer: Option C
Explanation:
Let the shares of A, B, C and D be Rs. 5x, Rs. 2x, Rs. 4x and Rs. 3x respectively.
Then, 4x – 3x = 1000
x = 1000.
B’s share = Rs. 2x = Rs. (2 x 1000) = Rs. 2000.
#4. Seats for Mathematics, Physics and Biology in a school are in the ratio 5 : 7 : 8. There is a proposal to increase these seats by 40%, 50% and 75% respectively. What will be the ratio of increased seats?
Answer: Option A
Explanation:
Originally, let the number of seats for Mathematics, Physics and Biology be 5x, 7x and 8x respectively.
Number of increased seats are (140% of 5x), (150% of 7x) and (175% of 8x).
![]() |
![]() |
140 | x 5x | ![]() |
, | ![]() |
150 | x 7x | ![]() |
and | ![]() |
175 | x 8x | ![]() |
100 | 100 | 100 |
![]() |
21x | and 14x. |
2 |
![]() |
21x | : 14x |
2 |
14x : 21x : 28x
2 : 3 : 4.
#5. In a mixture 60 litres, the ratio of milk and water 2 : 1. If this ratio is to be 1 : 2, then the quantity of water to be further added is:
Answer: Option D
Explanation:
Quantity of milk = | ![]() |
60 x | 2 | ![]() |
3 |
Quantity of water in it = (60- 40) litres = 20 litres.
New ratio = 1 : 2
Let quantity of water to be added further be x litres.
Then, milk : water = | ![]() |
40 | ![]() |
. |
20 x |
Now, | ![]() |
40 | ![]() |
= | 1 |
20 x | 2 |
20 x = 80
x = 60.
Quantity of water to be added = 60 litres.
#6. The ratio of the number of boys and girls in a college is 7 : 8. If the percentage increase in the number of boys and girls be 20% and 10% respectively, what will be the new ratio?
Answer: Option C
Explanation:
Originally, let the number of boys and girls in the college be 7x and 8x respectively.
Their increased number is (120% of 7x) and (110% of 8x).
![]() |
![]() |
120 | x 7x | ![]() |
and | ![]() |
110 | x 8x | ![]() |
100 | 100 |
![]() |
42x | and | 44x |
5 | 5 |
![]() |
![]() |
42x | : | 44x | ![]() |
= 21 : 22. |
5 | 5 |
#7. Salaries of Ravi and Sumit are in the ratio 2 : 3. If the salary of each is increased by Rs. 4000, the new ratio becomes 40 : 57. What is Sumit's salary?
Answer: Option D
Explanation:
Let the original salaries of Ravi and Sumit be Rs. 2x and Rs. 3x respectively.
Then, | 2x 4000 | = | 40 |
3x 4000 | 57 |
57(2x 4000) = 40(3x 4000)
6x = 68,000
3x = 34,000
Sumit’s present salary = (3x 4000) = Rs.(34000 4000) = Rs. 38,000.
#8. If 0.75 : x :: 5 : 8, then x is equal to:
Answer: Option B
Explanation:
(x x 5) = (0.75 x 8) ![]() |
![]() |
6 | ![]() |
= 1.20 |
5 |
#9. The sum of three numbers is 98. If the ratio of the first to second is 2 :3 and that of the second to the third is 5 : 8, then the second number is:
Answer: Option B
Explanation:
Let the three parts be A, B, C. Then,
A : B = 2 : 3 and B : C = 5 : 8 = | ![]() |
5 x | 3 | ![]() |
: | ![]() |
8 x | 3 | ![]() |
= 3 : | 24 |
5 | 5 | 5 |
![]() |
24 | = 10 : 15 : 24 |
5 |
![]() |
![]() |
98 x | 15 | ![]() |
= 30. |
49 |
#10. If Rs. 782 be divided into three parts, proportional to 1/2 : 2/3 : 3/4, then the first part is:
Answer: Option D
Explanation:
Given ratio = :
:
= 6 : 8 : 9.
![]() |
![]() |
782 x | 6 | ![]() |
= Rs. 204 |
23 |
#11. The salaries A, B, C are in the ratio 2 : 3 : 5. If the increments of 15%, 10% and 20% are allowed respectively in their salaries, then what will be new ratio of their salaries?
Answer: Option C
Explanation:
Let A = 2k, B = 3k and C = 5k.
A’s new salary = | 115 | of 2k = | ![]() |
115 | x 2k | ![]() |
= | 23k |
100 | 100 | 10 |
B’s new salary = | 110 | of 3k = | ![]() |
110 | x 3k | ![]() |
= | 33k |
100 | 100 | 10 |
C’s new salary = | 120 | of 5k = | ![]() |
120 | x 5k | ![]() |
= 6k |
100 | 100 |
![]() |
![]() |
23k | : | 33k | : 6k | ![]() |
= 23 : 33 : 60 |
10 | 10 |
#12. If 40% of a number is equal to two-third of another number, what is the ratio of first number to the second number?
Answer: Option C
Explanation:
Let 40% of A = | 2 | B |
3 |
Then, | 40A | = | 2B |
100 | 3 |
![]() |
2A | = | 2B |
5 | 3 |
![]() |
A | = | ![]() |
2 | x | 5 | ![]() |
= | 5 |
B | 3 | 2 | 3 |
A : B = 5 : 3.
#13. The fourth proportional to 5, 8, 15 is:
Answer: Option B
Explanation:
Let the fourth proportional to 5, 8, 15 be x.
Then, 5 : 8 : 15 : x
5x = (8 x 15)
x = | (8 x 15) | = 24. |
5 |
#14. Two number are in the ratio 3 : 5. If 9 is subtracted from each, the new numbers are in the ratio 12 : 23. The smaller number is:
Answer: Option B
Explanation:
Let the numbers be 3x and 5x.
Then, | 3x – 9 | = | 12 |
5x – 9 | 23 |
23(3x – 9) = 12(5x – 9)
9x = 99
x = 11.
The smaller number = (3 x 11) = 33.
#15. In a bag, there are coins of 25 p, 10 p and 5 p in the ratio of 1 : 2 : 3. If there is Rs. 30 in all, how many 5 p coins are there?
Answer: Option C
Explanation:
Let the number of 25 p, 10 p and 5 p coins be x, 2x, 3x respectively.
Then, sum of their values = Rs. | ![]() |
25x | 10 x 2x | 5 x 3x | ![]() |
= Rs. | 60x | ||
100 | 100 | 100 | 100 |
![]() |
60x | = 30 | ![]() |
30 x 100 | = 50. |
100 | 60 |
Hence, the number of 5 p coins = (3 x 50) = 150.
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