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### Instructions: This Monk test contains JK Bank Height and Distance Problems. This will help you in JK bank exam preparation.

• This is a FREE online JK Bank Monk Test on topic JK Bank train Problems with answer. You DO NOT pay money to anyone to attend this test.
• Each question carries 1 mark, no negative marks.
• DO NOT refresh the page.
• All the best :-).

## Results

### #1. A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?

Explanation:

 Speed = 60 x 5 m/sec = 50 m/sec. 18 3

Length of the train = (Speed x Time).

 Length of the train = 50 x 9 m = 150 m. 3

### #2. A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:

Explanation:

 Speed of the train relative to man = 125 m/sec 10
 = 25 m/sec. 2
 = 25 x 18 km/hr 2 5

= 45 km/hr.

Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr.

x – 5 = 45          x = 50 km/hr.

### #3. The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:

Explanation:

 Speed = 45 x 5 m/sec = 25 m/sec. 18 2

Time = 30 sec.

Let the length of bridge be x metres.

 Then, 130  x = 25 30 2

2(130  x) = 750

x = 245 m.

### #4. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:

Explanation:

Let the speeds of the two trains be x m/sec and y m/sec respectively.

Then, length of the first train = 27x metres,

and length of the second train = 17y metres.

 27x  17y = 23 x  y

27x  17y = 23x  23y

4x = 6y

 x = 3 . y 2

### #5. A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?

Explanation:

 Speed = 54 x 5 m/sec = 15 m/sec. 18

Length of the train = (15 x 20)m = 300 m.

Let the length of the platform be x metres.

 Then, x  300 = 15 36

x  300 = 540

x = 240 m.

### #6. A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?

Explanation:

 Speed = 240 m/sec = 10 m/sec. 24
 Required time = 240 650 sec = 89 sec. 10

### #7. Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:

Explanation:

Let the length of each train be x metres.

Then, distance covered = 2x metres.

Relative speed = (46 – 36) km/hr

 = 10 x 5 m/sec 18
 = 25 m/sec 9
 2x = 25 36 9

2x = 100

x = 50.

### #8. A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?

Explanation:

 Formula for converting from km/hr to m/s:   X km/hr = X x 5 m/s. 18
 Therefore, Speed = 45 x 5 m/sec = 25 m/sec. 18 2

Total distance to be covered = (360 140) m = 500 m.

 Formula for finding Time = Distance Speed
 Required time = 500 x 2 sec = 40 sec.

### #9. Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:

Explanation:

Relative speed = (60 90) km/hr

 = 150 x 5 m/sec 18
 = 125 m/sec. 3

Distance covered = (1.10 0.9) km = 2 km = 2000 m.

 Required time = 2000 x 3 sec = 48 sec. 125

### #10. A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?

Explanation:

Speed of train relative to jogger = (45 – 9) km/hr = 36 km/hr.

 = 36 x 5 m/sec 18

= 10 m/sec.

Distance to be covered = (240 120) m = 360 m.

 Time taken = 360 sec = 36 sec. 10

### #11. A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?

Explanation:

Relative speed = (120 80) km/hr

 = 200 x 5 m/sec 18
 = 500 m/sec. 9

Let the length of the other train be x metres.

 Then, x  270 = 500 9 9

x  270 = 500

x = 230.

### #12. A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?

Explanation:

 Speed = 72 x 5 m/sec = 20 m/sec. 18

Time = 26 sec.

Let the length of the train be x metres.

 Then, x  250 = 20 26

x  250 = 520

x = 270.

### #13. Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:

Explanation:

Let the speed of the slower train be x m/sec.

Then, speed of the faster train = 2x m/sec.

Relative speed = (x  2x) m/sec = 3x m/sec.

 (100 100) = 3x 8

24x = 200

 x = 25 . 3
 So, speed of the faster train = 50 m/sec 3
 = 50 x 18 km/hr 3 5

= 60 km/hr.

### #14. Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:

Explanation:

 Relative speed = (60 40) km/hr = 100 x 5 m/sec = 250 m/sec. 18 9

Distance covered in crossing each other = (140 160) m = 300 m.

 Required time = 300 x 9 sec = 54 sec = 10.8 sec. 250 5

### #15. A train travelling at a speed of 75 mph enters a tunnel 31/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?

Explanation:

Total distance covered
 = 7 1 miles 2 4
 = 15 miles. 4
Time taken
 = 15 hrs 4 x 75
 = 1 hrs 20
 = 1 x 60 min. 20
= 3 min.

### #16. A train 800 metres long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is:

Explanation:

 Speed = 78 x 5 m/sec = 65 m/sec. 18 3

Time = 1 minute = 60 seconds.

Let the length of the tunnel be x metres.

 Then, 800  x = 65 60 3

3(800  x) = 3900

x = 500.