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Results
#1. A train running at the speed of 60 km/hr crosses a pole in 9 seconds. What is the length of the train?
Answer: Option D
Explanation:
Speed = | ![]() |
60 x | 5 | ![]() |
= | ![]() |
50 | ![]() |
18 | 3 |
Length of the train = (Speed x Time).
![]() |
![]() |
50 | x 9 | ![]() |
3 |
#2. A train 125 m long passes a man, running at 5 km/hr in the same direction in which the train is going, in 10 seconds. The speed of the train is:
Answer: Option B
Explanation:
Speed of the train relative to man = | ![]() |
125 | ![]() |
10 |
= | ![]() |
25 | ![]() |
2 |
= | ![]() |
25 | x | 18 | ![]() |
2 | 5 |
= 45 km/hr.
Let the speed of the train be x km/hr. Then, relative speed = (x – 5) km/hr.
x – 5 = 45
x = 50 km/hr.
#3. The length of the bridge, which a train 130 metres long and travelling at 45 km/hr can cross in 30 seconds, is:
Answer: Option C
Explanation:
Speed = | ![]() |
45 x | 5 | ![]() |
= | ![]() |
25 | ![]() |
18 | 2 |
Time = 30 sec.
Let the length of bridge be x metres.
Then, | 130 x | = | 25 |
30 | 2 |
2(130 x) = 750
x = 245 m.
#4. Two trains running in opposite directions cross a man standing on the platform in 27 seconds and 17 seconds respectively and they cross each other in 23 seconds. The ratio of their speeds is:
Answer: Option B
Explanation:
Let the speeds of the two trains be x m/sec and y m/sec respectively.
Then, length of the first train = 27x metres,
and length of the second train = 17y metres.
![]() |
27x 17y | = 23 |
x y |
27x 17y = 23x 23y
4x = 6y
![]() |
x | = | 3 | . |
y | 2 |
#5. A train passes a station platform in 36 seconds and a man standing on the platform in 20 seconds. If the speed of the train is 54 km/hr, what is the length of the platform?
Answer: Option B
Explanation:
Speed = | ![]() |
54 x | 5 | ![]() |
18 |
Length of the train = (15 x 20)m = 300 m.
Let the length of the platform be x metres.
Then, | x 300 | = 15 |
36 |
x 300 = 540
x = 240 m.
#6. A train 240 m long passes a pole in 24 seconds. How long will it take to pass a platform 650 m long?
Answer: Option B
Explanation:
Speed = | ![]() |
240 | ![]() |
24 |
![]() |
![]() |
240 650 | ![]() |
10 |
#7. Two trains of equal length are running on parallel lines in the same direction at 46 km/hr and 36 km/hr. The faster train passes the slower train in 36 seconds. The length of each train is:
Answer: Option A
Explanation:
Let the length of each train be x metres.
Then, distance covered = 2x metres.
Relative speed = (46 – 36) km/hr
= | ![]() |
10 x | 5 | ![]() |
18 |
= | ![]() |
25 | ![]() |
9 |
![]() |
2x | = | 25 |
36 | 9 |
2x = 100
x = 50.
#8. A train 360 m long is running at a speed of 45 km/hr. In what time will it pass a bridge 140 m long?
Answer: Option A
Explanation:
Formula for converting from km/hr to m/s: X km/hr = | ![]() |
X x | 5 | ![]() |
m/s. |
18 |
Therefore, Speed = | ![]() |
45 x | 5 | ![]() |
= | 25 | m/sec. |
18 | 2 |
Total distance to be covered = (360 140) m = 500 m.
Formula for finding Time = | ![]() |
Distance | ![]() |
Speed |
![]() |
![]() |
500 x 2 | ![]() |
= 40 sec. |
#9. Two trains are moving in opposite directions @ 60 km/hr and 90 km/hr. Their lengths are 1.10 km and 0.9 km respectively. The time taken by the slower train to cross the faster train in seconds is:
Answer: Option C
Explanation:
Relative speed = (60 90) km/hr
= | ![]() |
150 x | 5 | ![]() |
18 |
= | ![]() |
125 | ![]() |
3 |
Distance covered = (1.10 0.9) km = 2 km = 2000 m.
Required time = | ![]() |
2000 x | 3 | ![]() |
125 |
#10. A jogger running at 9 kmph alongside a railway track in 240 metres ahead of the engine of a 120 metres long train running at 45 kmph in the same direction. In how much time will the train pass the jogger?
Answer: Option C
Explanation:
Speed of train relative to jogger = (45 – 9) km/hr = 36 km/hr.
= | ![]() |
36 x | 5 | ![]() |
18 |
= 10 m/sec.
Distance to be covered = (240 120) m = 360 m.
![]() |
![]() |
360 | ![]() |
= 36 sec. |
10 |
#11. A 270 metres long train running at the speed of 120 kmph crosses another train running in opposite direction at the speed of 80 kmph in 9 seconds. What is the length of the other train?
Answer: Option A
Explanation:
Relative speed = (120 80) km/hr
= | ![]() |
200 x | 5 | ![]() |
18 |
= | ![]() |
500 | ![]() |
9 |
Let the length of the other train be x metres.
Then, | x 270 | = | 500 |
9 | 9 |
x 270 = 500
x = 230.
#12. A goods train runs at the speed of 72 kmph and crosses a 250 m long platform in 26 seconds. What is the length of the goods train?
Answer: Option D
Explanation:
Speed = | ![]() |
72 x | 5 | ![]() |
= 20 m/sec. |
18 |
Time = 26 sec.
Let the length of the train be x metres.
Then, | x 250 | = 20 |
26 |
x 250 = 520
x = 270.
#13. Two trains, each 100 m long, moving in opposite directions, cross each other in 8 seconds. If one is moving twice as fast the other, then the speed of the faster train is:
Answer: Option C
Explanation:
Let the speed of the slower train be x m/sec.
Then, speed of the faster train = 2x m/sec.
Relative speed = (x 2x) m/sec = 3x m/sec.
![]() |
(100 100) | = 3x |
8 |
24x = 200
![]() |
25 | . |
3 |
So, speed of the faster train = | 50 | m/sec |
3 |
= | ![]() |
50 | x | 18 | ![]() |
3 | 5 |
= 60 km/hr.
#14. Two trains 140 m and 160 m long run at the speed of 60 km/hr and 40 km/hr respectively in opposite directions on parallel tracks. The time (in seconds) which they take to cross each other, is:
Answer: Option D
Explanation:
Relative speed = (60 40) km/hr = | ![]() |
100 x | 5 | ![]() |
= | ![]() |
250 | ![]() |
18 | 9 |
Distance covered in crossing each other = (140 160) m = 300 m.
Required time = | ![]() |
300 x | 9 | ![]() |
= | 54 | sec = 10.8 sec. |
250 | 5 |
#15. A train travelling at a speed of 75 mph enters a tunnel 31/2 miles long. The train is 1/4 mile long. How long does it take for the train to pass through the tunnel from the moment the front enters to the moment the rear emerges?
Answer: Option B
Explanation:
Total distance covered |
|
|||||||||
|
![]() |
|
|||||||
|
||||||||
|
||||||||
= 3 min. |
#16. A train 800 metres long is running at a speed of 78 km/hr. If it crosses a tunnel in 1 minute, then the length of the tunnel (in meters) is:
Answer: Option C
Explanation:
Speed = | ![]() |
78 x | 5 | ![]() |
m/sec | = | ![]() |
65 | ![]() |
m/sec. |
18 | 3 |
Time = 1 minute = 60 seconds.
Let the length of the tunnel be x metres.
Then, | ![]() |
800 x | ![]() |
= | 65 |
60 | 3 |
3(800 x) = 3900
x = 500.
#17. 300 metre long train crosses a platform in 39 seconds while it crosses a signal pole in 18 seconds. What is the length of the platform?
Answer: Option B
Explanation:
Speed = | ![]() |
300 | ![]() |
m/sec = | 50 | m/sec. |
18 | 3 |
Let the length of the platform be x metres.
Then, | ![]() |
x 300 | ![]() |
= | 50 |
39 | 3 |
3(x 300) = 1950
x = 350 m.
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