Instructions: This Monk test contains JK Bank Probability Problems with answer. This will help you in JK bank exam preparation.
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Directions to Solve
In the following the questions choose the word which best expresses the meaning of the given word.
Results
#1. Tickets numbered 1 to 20 are mixed up and then a ticket is drawn at random. What is the probability that the ticket drawn has a number which is a multiple of 3 or 5?
Answer: Option D
Explanation:
Here, S = {1, 2, 3, 4, …., 19, 20}.
Let E = event of getting a multiple of 3 or 5 = {3, 6 , 9, 12, 15, 18, 5, 10, 20}.
P(E) =  n(E)  =  9  . 
n(S)  20 
#2. A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
Answer: Option A
Explanation:
Total number of balls = (2 3 2) = 7.
Let S be the sample space.
Then, n(S)  = Number of ways of drawing 2 balls out of 7  
= ^{7}C_{2} `  


= 21. 
Let E = Event of drawing 2 balls, none of which is blue.
n(E)  = Number of ways of drawing 2 balls out of (2 3) balls.  
= ^{5}C_{2}  


= 10. 
P(E) =  n(E)  =  10  . 
n(S)  21 
#3. In a box, there are 8 red, 7 blue and 6 green balls. One ball is picked up randomly. What is the probability that it is neither red nor green?
Answer: Option A
Explanation:
Total number of balls = (8 7 6) = 21.
Let E  = event that the ball drawn is neither red nor green 
= event that the ball drawn is blue. 
n(E) = 7.
P(E) =  n(E)  =  7  =  1  . 
n(S)  21  3 
#4. What is the probability of getting a sum 9 from two throws of a dice?
Answer: Option C
Explanation:
In two throws of a dice, n(S) = (6 x 6) = 36.
Let E = event of getting a sum ={(3, 6), (4, 5), (5, 4), (6, 3)}.
P(E) =  n(E)  =  4  =  1  . 
n(S)  36  9 
#5. Three unbiased coins are tossed. What is the probability of getting at most two heads?
Answer: Option D
Explanation:
Here S = {TTT, TTH, THT, HTT, THH, HTH, HHT, HHH}
Let E = event of getting at most two heads.
Then E = {TTT, TTH, THT, HTT, THH, HTH, HHT}.
P(E) =  n(E)  =  7  . 
n(S)  8 
#6. Two dice are thrown simultaneously. What is the probability of getting two numbers whose product is even?
Answer: Option B
Explanation:
In a simultaneous throw of two dice, we have n(S) = (6 x 6) = 36.
Then, E  = {(1, 2), (1, 4), (1, 6), (2, 1), (2, 2), (2, 3), (2, 4), (2, 5), (2, 6), (3, 2), (3, 4), (3, 6), (4, 1), (4, 2), (4, 3), (4, 4), (4, 5), (4, 6), (5, 2), (5, 4), (5, 6), (6, 1), (6, 2), (6, 3), (6, 4), (6, 5), (6, 6)} 
n(E) = 27.
P(E) =  n(E)  =  27  =  3  . 
n(S)  36  4 
#7. In a class, there are 15 boys and 10 girls. Three students are selected at random. The probability that 1 girl and 2 boys are selected, is:
Answer: Option A
Explanation:
Let S be the sample space and E be the event of selecting 1 girl and 2 boys.
Then, n(S)  = Number ways of selecting 3 students out of 25  
= ^{25}C_{3} `  


= 2300. 
n(E)  = (^{10}C_{1} x ^{15}C_{2})  


= 1050. 
P(E) =  n(E)  =  1050  =  21  . 
n(S)  2300  46 
#8. In a lottery, there are 10 prizes and 25 blanks. A lottery is drawn at random. What is the probability of getting a prize?
Answer: Option C
Explanation:
P (getting a prize) =  10  =  10  =  2  . 
(10 25)  35  7 
#9. From a pack of 52 cards, two cards are drawn together at random. What is the probability of both the cards being kings?
Answer: Option D
Explanation:
Let S be the sample space.
Then, n(S) = ^{52}C_{2} =  (52 x 51)  = 1326. 
(2 x 1) 
Let E = event of getting 2 kings out of 4.
n(E) = ^{4}C_{2} =  (4 x 3)  = 6. 
(2 x 1) 
P(E) =  n(E)  =  6  =  1  . 
n(S)  1326  221 
#10. Two dice are tossed. The probability that the total score is a prime number is:
Answer: Option B
Explanation:
Clearly, n(S) = (6 x 6) = 36.
Let E = Event that the sum is a prime number.
Then E  = { (1, 1), (1, 2), (1, 4), (1, 6), (2, 1), (2, 3), (2, 5), (3, 2), (3, 4), (4, 1), (4, 3), (5, 2), (5, 6), (6, 1), (6, 5) } 
n(E) = 15.
P(E) =  n(E)  =  15  =  5  . 
n(S)  36  12 
#11. A card is drawn from a pack of 52 cards. The probability of getting a queen of club or a king of heart is:
Answer: Option C
Explanation:
Here, n(S) = 52.
Let E = event of getting a queen of club or a king of heart.
Then, n(E) = 2.
P(E) =  n(E)  =  2  =  1  . 
n(S)  52  26 
#12. A bag contains 4 white, 5 red and 6 blue balls. Three balls are drawn at random from the bag. The probability that all of them are red, is:
Answer: Option C
Explanation:
Let S be the sample space.
Then, n(S)  = number of ways of drawing 3 balls out of 15  
= ^{15}C_{3}  


= 455. 
Let E = event of getting all the 3 red balls.
n(E) = ^{5}C_{3} = ^{5}C_{2} =  (5 x 4)  = 10. 
(2 x 1) 
P(E) =  n(E)  =  10  =  2  . 
n(S)  455  91 
#13. Two cards are drawn together from a pack of 52 cards. The probability that one is a spade and one is a heart, is:
Answer: Option D
Explanation:
Let S be the sample space.
Then, n(S) = ^{52}C_{2} =  (52 x 51)  = 1326. 
(2 x 1) 
Let E = event of getting 1 spade and 1 heart.
n(E)  = number of ways of choosing 1 spade out of 13 and 1 heart out of 13 
= (^{13}C_{1} x ^{13}C_{1})  
= (13 x 13)  
= 169. 
P(E) =  n(E)  =  169  =  13  . 
n(S)  1326  102 
#14. One card is drawn at random from a pack of 52 cards. What is the probability that the card drawn is a face card (Jack, Queen and King only)?
Answer: Option B
Explanation:
Clearly, there are 52 cards, out of which there are 12 face cards.
P (getting a face card) =  12  =  3  . 
52  13 
#15. A bag contains 6 black and 8 white balls. One ball is drawn at random. What is the probability that the ball drawn is white?
Answer: Option B
Explanation:
Let number of balls = (6 8) = 14.
Number of white balls = 8.
P (drawing a white ball) =  8  =  4  . 
14  7 
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