Instructions: This Monk test contains JK Bank Percentage Problems with answer. This will help you in JK bank exam preparation.
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Results
#1. A batsman scored 110 runs which included 3 boundaries and 8 sixes. What percent of his total score did he make by running between the wickets?
Answer: Option B
Explanation:
Number of runs made by running = 110 – (3 x 4 8 x 6)
= 110 – (60)
= 50.
Required percentage = | 50 | x 100 | % = 45 | 5 | % | |
110 | 11 |
#2. Two students appeared at an examination. One of them secured 9 marks more than the other and his marks was 56% of the sum of their marks. The marks obtained by them are:
Answer: Option C
Explanation:
Let their marks be (x 9) and x.
Then, x 9 = | 56 | (x 9 x) |
100 |
25(x 9) = 14(2x 9)
3x = 99
x = 33
So, their marks are 42 and 33.
#3. A fruit seller had some apples. He sells 40% apples and still has 420 apples. Originally, he had:
Answer: Option D
Explanation:
Suppose originally he had x apples.
Then, (100 – 40)% of x = 420.
60 | x x = 420 | |
100 |
x = | 420 x 100 | = 700. | |
60 |
#4. What percentage of numbers from 1 to 70 have 1 or 9 in the unit's digit?
Answer: Option C
Explanation:
Clearly, the numbers which have 1 or 9 in the unit’s digit, have squares that end in the digit 1. Such numbers from 1 to 70 are 1, 9, 11, 19, 21, 29, 31, 39, 41, 49, 51, 59, 61, 69.
Number of such number =14
Required percentage = | 14 | x 100 | % = 20%. | |
70 |
#5. If A = x% of y and B = y% of x, then which of the following is true?
Answer: Option E
Explanation:
x% of y = | x | x y | = | y | x x | = y% of x | ||||
100 | 100 |
A = B.
#6. If 20% of a = b, then b% of 20 is the same as:
Answer: Option A
Explanation:
20% of a = b | 20 | a = b. |
100 |
b% of 20 = | b | x 20 | = | 20 | a x | 1 | x 20 | = | 4 | a = 4% of a. | ||||
100 | 100 | 100 | 100 |
#7. In a certain school, 20% of students are below 8 years of age. The number of students above 8 years of age is of the number of students of 8 years of age which is 48. What is the total number of students in the school?
Answer: Option E
Explanation:
Let the number of students be x. Then,
Number of students above 8 years of age = (100 – 20)% of x = 80% of x.
80% of x = 48 | 2 | of 48 |
3 |
80 | x = 80 | |
100 |
x = 100.
#8. Two numbers A and B are such that the sum of 5% of A and 4% of B is two-third of the sum of 6% of A and 8% of B. Find the ratio of A : B.
Answer: Option D
Explanation:
5% of A 4% of B = | 2 | (6% of A 8% of B) |
3 |
5 | A | 4 | B | = | 2 | 6 | A | 8 | B | |||
100 | 100 | 3 | 100 | 100 |
1 | A | 1 | B | = | 1 | A | 4 | B | |
20 | 25 | 25 | 75 |
1 | – | 1 | A = | 4 | – | 1 | B | |||
20 | 25 | 75 | 25 |
1 | A = | 1 | B | |
100 | 75 |
A | = | 100 | = | 4 | . |
B | 75 | 3 |
Required ratio = 4 : 3
#9. A student multiplied a number by 3/5 instead of 5/3. What is the percentage error in the calculation?
Answer: Option D
Explanation:
Let the number be x.
Then, error = | 5 | x – | 3 | x = | 16 | x. |
3 | 5 | 15 |
Error% = | 16x | x | 3 | x 100 | %= 64%. | |
15 | 5x |
#10. In an election between two candidates, one got 55% of the total valid votes, 20% of the votes were invalid. If the total number of votes was 7500, the number of valid votes that the other candidate got, was:
Answer: Option A
Explanation:
Number of valid votes = 80% of 7500 = 6000.
Valid votes polled by other candidate = 45% of 6000
= | 45 | x 6000 | = 2700. | ||
100 |
#11. Three candidates contested an election and received 1136, 7636 and 11628 votes respectively. What percentage of the total votes did the winning candidate get?
Answer: Option A
Explanation:
Total number of votes polled = (1136 7636 11628) = 20400.
Required percentage = | 11628 | x 100 | % = 57%. | |
20400 |
#12. Two tailors X and Y are paid a total of Rs. 550 per week by their employer. If X is paid 120 percent of the sum paid to Y, how much is Y paid per week?
Answer: Option B
Explanation:
Let the sum paid to Y per week be Rs. z.
Then, z 120% of z = 550.
z | 120 | z = 550 |
100 |
11 | z = 550 | |
5 |
z = | 550 x 5 | = 250. | |
11 |
#13. Gauri went to the stationers and bought things worth Rs. 25, out of which 30 paise went on sales tax on taxable purchases. If the tax rate was 6%, then what was the cost of the tax free items?
Answer: Option C
Explanation:
Let the amount taxable purchases be Rs. x.
Then, 6% of x = | 30 |
100 |
x = | 30 | x | 100 | = 5. | |
100 | 6 |
Cost of tax free items = Rs. [25 – (5 0.30)] = Rs. 19.70
#14. Rajeev buys good worth Rs. 6650. He gets a rebate of 6% on it. After getting the rebate, he pays sales tax @ 10%. Find the amount he will have to pay for the goods.
Answer: Option A
Explanation:
Rebate = 6% of Rs. 6650 = Rs. | 6 | x 6650 | = Rs. 399. | ||
100 |
Sales tax = 10% of Rs. (6650 – 399) = Rs. | 10 | x 6251 | = Rs. 625.10 | ||
100 |
Final amount = Rs. (6251 625.10) = Rs. 6876.10
#15. The population of a town increased from 1,75,000 to 2,62,500 in a decade. The average percent increase of population per year is:
Answer: Option B
Explanation:
Increase in 10 years = (262500 – 175000) = 87500.
Increase% = | 87500 | x 100 | % = 50%. | |
175000 |
Required average = | 50 | % = 5%. | |
10 |
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