JK Bank Calendar Problems with answer-Monk Test 2020

On 31^st December, 2005 it was Saturday. Number of odd days from the year 2006 to the year 2009 = (1 1 2 1) = 5 days.  On 31^st December 2009, it was Thursday. Thus, on 1^st Jan, 2010 it is Friday.

17^th June, 1998 = (1997 years Period from 1.1.1998 to 17.6.1998)

Odd days in 1600 years = 0

Odd days in 300 years = (5 x 3)  1

97 years has 24 leap years 73 ordinary years.

Number of odd days in 97 years ( 24 x 2 73) = 121 = 2 odd days.

Jan.  Feb.   March    April    May      June 
(31    28     31       30       31       17) = 168 days

 168 days = 24 weeks = 0 odd day.

Total number of odd days = (0 1 2 0) = 3.

Given day is Wednesday.

Each day of the week is repeated after 7 days.

So, after 63 days, it will be Monday.

 After 61 days, it will be Saturday.

The year 2004 is a leap year. So, it has 2 odd days.

But, Feb 2004 not included because we are calculating from March 2004 to March 2005. So it has 1 odd day only.

 The day on 6^th March, 2005 will be 1 day beyond the day on 6^th March, 2004.

Given that, 6^th March, 2005 is Monday.

 6^th March, 2004 is Sunday (1 day before to 6^th March, 2005).

We shall find the day on 1^st April, 2001.1^st April, 2001 = (2000 years Period from 1.1.2001 to 1.4.2001)

Odd days in 1600 years = 0

Odd days in 400 years = 0

Jan. Feb. March April
(31 28 31 1)     = 91 days  0 odd days.

Total number of odd days = (0 0 0) = 0

On 1^st April, 2001 it was Sunday.

In April, 2001 Wednesday falls on 4^th, 11^th, 18^th and 25^th.

x weeks x days = (7x   x) days = 8x days.

100 years contain 5 odd days.

 Last day of 1^st century is Friday.

200 years contain (5 x 2)  3 odd days.

 Last day of 2^nd century is Wednesday.

300 years contain (5 x 3) = 15  1 odd day.

 Last day of 3^rd century is Monday.

400 years contain 0 odd day.

 Last day of 4^th century is Sunday.

This cycle is repeated.

 Last day of a century cannot be Tuesday or Thursday or Saturday.

The year 2004 is a leap year. It has 2 odd days.

 The day on 8^th Feb, 2004 is 2 days before the day on 8^th Feb, 2005.

Hence, this day is Sunday.

The century divisible by 400 is a leap year.

 The year 700 is not a leap year.

The year 2006 is an ordinary year. So, it has 1 odd day.

So, the day on 8^th Dec, 2007 will be 1 day beyond the day on 8^th Dec, 2006.

But, 8^th Dec, 2007 is Saturday.

 8^th Dec, 2006 is Friday.

The year 2008 is a leap year. So, it has 2 odd days.

1^st day of the year 2008 is Tuesday (Given)

So, 1^st day of the year 2009 is 2 days beyond Tuesday.

Hence, it will be Thursday.

The year 2007 is an ordinary year. So, it has 1 odd day.

1^st day of the year 2007 was Monday.

1^st day of the year 2008 will be 1 day beyond Monday.

Hence, it will be Tuesday.